- 15√3 cm
^{3} - 12√2 cm
^{3} - 18√2 cm
^{3} - 21 cm
^{3}

Option 3 : 18√2 cm^{3}

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Since a regular tetrahedron is nothing but a regular pyramid with base as equilateral triangle.

Thus, volume of tetrahedron = 1/3 × area of base × height = 1/3 × √3/4 a^{2} × a√6/3 = a^{3}/(6√2)

= 6 × 6 × 6/(6√2) = 18√2 cm^{3}

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